x^2-0.79x+0.052=0

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Solution for x^2-0.79x+0.052=0 equation:



x^2-0.79x+0.052=0
a = 1; b = -0.79; c = +0.052;
Δ = b2-4ac
Δ = -0.792-4·1·0.052
Δ = 0.4161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.79)-\sqrt{0.4161}}{2*1}=\frac{0.79-\sqrt{0.4161}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.79)+\sqrt{0.4161}}{2*1}=\frac{0.79+\sqrt{0.4161}}{2} $

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